0=16x^2+64x+512

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Solution for 0=16x^2+64x+512 equation: 



0=16x^2+64x+512

We move all terms to the left:

0-(16x^2+64x+512)=0

We add all the numbers together, and all the variables

-(16x^2+64x+512)=0

We get rid of parentheses

-16x^2-64x-512=0

a = -16; b = -64; c = -512;
Δ = b2-4ac
Δ = -642-4·(-16)·(-512)
Δ = -28672
Delta is less than zero, so there is no solution for the equation

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